Integrand size = 31, antiderivative size = 76 \[ \int \frac {\left (c+d x^{2 n}\right )^p}{\left (a-b x^n\right ) \left (a+b x^n\right )} \, dx=\frac {x \left (c+d x^{2 n}\right )^p \left (1+\frac {d x^{2 n}}{c}\right )^{-p} \operatorname {AppellF1}\left (\frac {1}{2 n},1,-p,\frac {1}{2} \left (2+\frac {1}{n}\right ),\frac {b^2 x^{2 n}}{a^2},-\frac {d x^{2 n}}{c}\right )}{a^2} \]
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Time = 0.04 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.097, Rules used = {531, 441, 440} \[ \int \frac {\left (c+d x^{2 n}\right )^p}{\left (a-b x^n\right ) \left (a+b x^n\right )} \, dx=\frac {x \left (c+d x^{2 n}\right )^p \left (\frac {d x^{2 n}}{c}+1\right )^{-p} \operatorname {AppellF1}\left (\frac {1}{2 n},1,-p,\frac {1}{2} \left (2+\frac {1}{n}\right ),\frac {b^2 x^{2 n}}{a^2},-\frac {d x^{2 n}}{c}\right )}{a^2} \]
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Rule 440
Rule 441
Rule 531
Rubi steps \begin{align*} \text {integral}& = \int \frac {\left (c+d x^{2 n}\right )^p}{a^2-b^2 x^{2 n}} \, dx \\ & = \left (\left (c+d x^{2 n}\right )^p \left (1+\frac {d x^{2 n}}{c}\right )^{-p}\right ) \int \frac {\left (1+\frac {d x^{2 n}}{c}\right )^p}{a^2-b^2 x^{2 n}} \, dx \\ & = \frac {x \left (c+d x^{2 n}\right )^p \left (1+\frac {d x^{2 n}}{c}\right )^{-p} F_1\left (\frac {1}{2 n};1,-p;\frac {1}{2} \left (2+\frac {1}{n}\right );\frac {b^2 x^{2 n}}{a^2},-\frac {d x^{2 n}}{c}\right )}{a^2} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(258\) vs. \(2(76)=152\).
Time = 0.48 (sec) , antiderivative size = 258, normalized size of antiderivative = 3.39 \[ \int \frac {\left (c+d x^{2 n}\right )^p}{\left (a-b x^n\right ) \left (a+b x^n\right )} \, dx=\frac {a^2 c (1+2 n) x \left (c+d x^{2 n}\right )^p \operatorname {AppellF1}\left (\frac {1}{2 n},-p,1,1+\frac {1}{2 n},-\frac {d x^{2 n}}{c},\frac {b^2 x^{2 n}}{a^2}\right )}{\left (a^2-b^2 x^{2 n}\right ) \left (2 a^2 d n p x^{2 n} \operatorname {AppellF1}\left (1+\frac {1}{2 n},1-p,1,2+\frac {1}{2 n},-\frac {d x^{2 n}}{c},\frac {b^2 x^{2 n}}{a^2}\right )+2 b^2 c n x^{2 n} \operatorname {AppellF1}\left (1+\frac {1}{2 n},-p,2,2+\frac {1}{2 n},-\frac {d x^{2 n}}{c},\frac {b^2 x^{2 n}}{a^2}\right )+a^2 c (1+2 n) \operatorname {AppellF1}\left (\frac {1}{2 n},-p,1,1+\frac {1}{2 n},-\frac {d x^{2 n}}{c},\frac {b^2 x^{2 n}}{a^2}\right )\right )} \]
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\[\int \frac {\left (c +d \,x^{2 n}\right )^{p}}{\left (a -b \,x^{n}\right ) \left (a +b \,x^{n}\right )}d x\]
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\[ \int \frac {\left (c+d x^{2 n}\right )^p}{\left (a-b x^n\right ) \left (a+b x^n\right )} \, dx=\int { -\frac {{\left (d x^{2 \, n} + c\right )}^{p}}{{\left (b x^{n} + a\right )} {\left (b x^{n} - a\right )}} \,d x } \]
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Exception generated. \[ \int \frac {\left (c+d x^{2 n}\right )^p}{\left (a-b x^n\right ) \left (a+b x^n\right )} \, dx=\text {Exception raised: HeuristicGCDFailed} \]
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\[ \int \frac {\left (c+d x^{2 n}\right )^p}{\left (a-b x^n\right ) \left (a+b x^n\right )} \, dx=\int { -\frac {{\left (d x^{2 \, n} + c\right )}^{p}}{{\left (b x^{n} + a\right )} {\left (b x^{n} - a\right )}} \,d x } \]
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\[ \int \frac {\left (c+d x^{2 n}\right )^p}{\left (a-b x^n\right ) \left (a+b x^n\right )} \, dx=\int { -\frac {{\left (d x^{2 \, n} + c\right )}^{p}}{{\left (b x^{n} + a\right )} {\left (b x^{n} - a\right )}} \,d x } \]
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Timed out. \[ \int \frac {\left (c+d x^{2 n}\right )^p}{\left (a-b x^n\right ) \left (a+b x^n\right )} \, dx=-\int -\frac {{\left (c+d\,x^{2\,n}\right )}^p}{a^2-b^2\,x^{2\,n}} \,d x \]
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